Method of undetermined coefficients problem

warfreak131
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I have the problem "Find the particular solution of 4y''+4y'+y=3xex.

What would be the assumed function y? Like would it be Ax ex?
 
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It would be more like Axe^x+Be^x.
 
ok, thanks, ill try that
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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