Methods that were used to solve the ODE

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The discussion revolves around transforming the equation xy = c(y + √(y² - x²)) into the form y² - cx = y√(y² - x²). Participants explore whether this transformation can be achieved through algebraic manipulation, emphasizing the equivalence of the two expressions. A key suggestion involves rationalizing the right-hand side of the equation, which may clarify the relationship between the two forms. The importance of regularly practicing algebra to improve skills is also highlighted. Ultimately, the conversation underscores the challenge of identifying the right algebraic techniques to solve such problems.
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Can anyone show me how to make this:

xy=c\left( y+\sqrt{y^2-x^2}\right)

Look like this:

y^2-cx=y\sqrt{ y^2-x^2}

These were given as the answers to an ODE problem.

I'm assuming that they are equivalent because they are presented in the answer as:

y^2-cx=y\sqrt{ y^2-x^2}, or equivalently xy=c\left( y+\sqrt{y^2-x^2}\right)

I got the second answer but I can't figure out how to algebraically manipulated it to make look like the first.

Any takers?

P.S. I'm not certain if it can even be done algebraically. It might have something to do with the methods that were used to solve the ODE. But if they are equivalent answers it should be possible to obtain one from the other using just algebra shouldn't it?

My algebra skills suck!
 
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It's true iff it can be proven algebraically. (Hurrah for abstract mathematics)

The method might become clear if you try solving both equations for c.

Better hint in white:


Try "rationalizing" the RHS -- multiply through by y - √(y2 - x2). (and handle specially the case where this actually equals zero)
 
Hurkyl said:
Try "rationalizing" --
Ok, that was specifically the hint that I needed. :biggrin:

I guess I need to start doing some algebra problems everyday like morning calisthenics or something. It's hard to do algebra if you aren't doing it every day. I pretty much know how to do all the tricks, I just can never figure out which trick to pull out of the bag to achieve my final goals!

Thanks for the tip! :approve:
 
Just FYI, I solved for c first. I figured rationalizing was the way to go, because one expression had the radical in the numerator, and the other on the denominator.
 
Hurkyl said:
Just FYI, I solved for c first. I figured rationalizing was the way to go, because one expression had the radical in the numerator, and the other on the denominator.
That little tid-bit of wisdom will definitely be useful to me in the future. To be perfectly honest, I'm so rusty with algebra that even that hint starting me in the face wouldn't have done much for me. But from now on when I see that situation I'll be thinking "rationalize!" :wink:

I'm just so rusty it's embarrassing. :blushing:
 
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