hellfire said:
Right now I do not understand where do [P&S] assume real
mass, and what would change in the (2.53) result if the mass would be complex.
OK, let's go back a bit further to P&S's eqn(2.20), i.e: the equal-time CCRs for a continuous
system. In particular, the 2nd part which says
<br />
[ \phi(\bold{x}) , \phi(\bold{y}) ] = 0 .<br />
This is an
assumption, motivated by imagining infinitesimal harmonic oscillators at
every point of spacetime. This is where the restriction to non-tachyonic fields is silently
introduced. But that choice of CCR was itself motivated by considering harmonic
oscillators, so the assumptions therein must be looked at more closely.
Also, look a bit further down the page at eqns (2.22) and (2.23), i.e.,
<br />
\omega_{\bold{p}} = \sqrt{|\bold{p}|^2 + m^2} ~~~~~ (2.22)<br />
If m is imaginary, \omega_{\bold{p}} is no longer real in general.
Similarly, looking at:
<br />
\phi = \frac{1}{\sqrt{2\omega}}(a + a^\dagger) ~~~~~~ (2.23)<br />
we see that \phi is no longer guaranteed to be Hermitian, if \omega is complex.
That makes it extremely difficult to get a sensible Hilbert space with +ve-definite
Hermitian inner product.
Basically, all the usual Fourier expansions assume that one can decompose
the field into (sums/integrals of) sines and cosines. But if the harmonic oscillator
eqn has imaginary mass, one must use sinh and cosh instead, and vast amounts
of the familiar Fourier machinery from the real-mass case become inapplicable.
I do not understand why is it required to make use of 4D Fourier transforms.
Actually, I do not understand neither why (2.40) of P&S is relevant here.
I suggested you look at 4D Fourier transforms to get an idea of what goes wrong.
Proving (2.40) gives insight into the way the p^0 poles occur on the real axis, and
by restricting to positive energy, we choose whether to close the contour in the upper
half place, and how to deform it around the poles to conform with our choice.
For imaginary mass, the poles are no longer on the real axis, and it is no longer
physically reasonable to restrict to one sign of p^0 (because here it's possible
to pass from +ve to -ve p^0 via a continuous Lorentz transformation).
But maybe the essence of your original question is more directly addressed by
just looking a bit further back, as I've sketched above.