Min weight of elevator accelerating, constant velocity, decelerating

AI Thread Summary
The discussion revolves around calculating the minimum scale reading for Liz in an elevator during its trip. The elevator accelerates from rest between the 1st and 2nd floors, moves at a constant velocity between the 2nd and 5th floors, and decelerates before stopping at the 6th floor. The equations used include N + Ma = Mg for acceleration and N - Ma = Mg for deceleration, with Liz's mass determined to be 8 kg. The minimum scale reading occurs during the acceleration phase, and the poster resolves their confusion about the calculations. The final answer confirms the correct understanding of the physics involved.
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Homework Statement



Starting from rest, an elevator accelerates uniformly between the 1st and 2nd floors, and decelerates uniformly between the 5th and 6th floors, coming to a stop at the 6th floor. Between the 2nd and 5th floors, the elevator covers the 6 meter distance between each two adjacent floors in 1 second. Inside, Liz (who is about to graduate) is standing on a scale that reads 800 N when the elevator isn't moving. What was her minimum scale reading during the trip? Use g = 10 m/s^2.

Homework Equations


The Attempt at a Solution



From 1st floor to second floor the equation would be N + Ma = Mg.
From second floor to fifth, it moves with constant velocity i.e 6 m/s
From fifth to sixth, the equation would be N - Ma= Mg.

Here, from the given data in question M = 8kgs.
How do I find the minimum reading?
 
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Never mind. Was making a silly mistake. Got it.
 
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