Minimum Force to Lift a Cylinder: Explained

AI Thread Summary
To lift a cylinder over a step with minimum force, the torque exerted by the lifting force must equal the torque due to the weight of the cylinder. This balance ensures that there is no angular acceleration, indicating that the force applied is at its minimum. The angle at which the force is applied plays a crucial role in achieving this minimum force while still producing the necessary torque. Understanding the distinction between torque and momentum is essential for solving the problem effectively. The discussion clarifies that the minimum force is directly related to the torque balance required to lift the cylinder.
asi123
Messages
254
Reaction score
0

Homework Statement



Hey, guys.
I have this guy trying to lift this cylinder pass the step with minimum force and so is the question, what's the minimum power that he needs to use and at what angle (alpha)?
I also added the solution.
The thing I don't understand is, why when the momentum of the weight and the momentum of the force equal one to another, you can say that the force is minimum? I mean, I can understand that there's no angular acceleration, but why is it minimum (the force)?
10x.

Homework Equations





The Attempt at a Solution

 

Attachments

  • 1.jpg
    1.jpg
    14.6 KB · Views: 420
Physics news on Phys.org
asi123 said:
The thing I don't understand is, why when the momentum of the weight and the momentum of the force equal one to another, you can say that the force is minimum?
You mean (I presume) moment (or torque) not momentum. The torque due to the weight is what the man must overcome to lift the cylinder over the step. So the minimum torque that he must exert is equal to the torque due to the weight. Of course, he'd choose an appropriate angle to use the minimum force to produce that torque.
 
Doc Al said:
You mean (I presume) moment (or torque) not momentum. The torque due to the weight is what the man must overcome to lift the cylinder over the step. So the minimum torque that he must exert is equal to the torque due to the weight. Of course, he'd choose an appropriate angle to use the minimum force to produce that torque.

Thanks.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top