Minimum Power Needed to Accelerate Air from Rest to 15 m/s

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To determine the minimum power required to accelerate 2 m³/min of air to 15 m/s, the density of air (1.25 kg/m³) must be used to convert volume to mass. The key formula involves calculating the force based on the change in momentum, which is mass times velocity. Power can then be calculated using the formula: Power = force times velocity. The discussion emphasizes that acceleration is not needed for this calculation, as the focus is on the rate of change of momentum. Understanding these concepts is crucial for solving the problem effectively.
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Homework Statement



A fan accelerates 2 m^3/min of air from rest to a velocity of 15 m/s. If the density of air is 1.25 kg/m^3, determine the minimum power that must be supplied to the fan?

Homework Equations





The Attempt at a Solution



Need some hints or something.
 
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welcome to pf!

hi arpsachin2! welcome to pf! :smile:

(try using the X2 icon just above the Reply box :wink:)

hint: momentum :wink:
 
Thank you.

Okay a bit more I guess. :(
 
You can convert the volume of air to mass using density.
 
(just got up :zzz: …)

force = rate of change of momentum

power = force times … ? :wink:
 
Power = force * velocity

Am I heading the right way?Fan accelerates at 2m^3/60 secs to 15 m/s

And density is 1.25kg/m^3.

So is it Power = 1.25kg/m^3 * Acceleration?

How do I get the acceleration?
 
hi arpsachin2! :smile:
arpsachin2 said:
Power = force * velocity

Am I heading the right way?

yes :smile:
Fan accelerates at 2m^3/60 secs to 15 m/s

And density is 1.25kg/m^3.

So is it Power = 1.25kg/m^3 * Acceleration?

and now you've totally lost me! :confused:

you don't need the acceleration!

you only need the force, and you can get that from the change in momentum :smile:
 
if possible could you show me an example or something?

Thanks
 
tiny-tim said:
hi arpsachin2! :smile:


yes :smile:


and now you've totally lost me! :confused:

you don't need the acceleration!

you only need the force, and you can get that from the change in momentum :smile:

Hey,

would it be possible to chat on Gmail or yahoo or something?
Please
 
  • #10
tiny-tim said:
hi arpsachin2! :smile:


yes :smile:


and now you've totally lost me! :confused:

you don't need the acceleration!

you only need the force, and you can get that from the change in momentum :smile:

So change in momentum is

Final momentum - Initial Momentum right

So, would it be 15 m/s - xxxx?
 
  • #11
hi arpsachin2! :smile:

(just got up :zzz: …)
arpsachin2 said:
So change in momentum is

Final momentum - Initial Momentum right

So, would it be 15 m/s - xxxx?

15 m/s is a speed, you need a momentum (= mass times speed), in kg m/s,

and then you need a rate of change of momentum, in kg m/s2
 
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