Minimum Speeds for 100g Particles on Energy/Distance Graph

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To determine the minimum speed a 100 g particle needs to travel between two points A and B using the energy versus distance graph, one must apply the conservation of energy principle. The minimum kinetic energy required to move from A to B can be calculated by finding the total work done, which involves integrating the force over distance. If gravitational potential energy is involved, the energy lost in potential energy translates to an equivalent gain in kinetic energy. The equation KE = 1/2 mv^2 can be used to solve for the speed after calculating the necessary kinetic energy. The discussion also highlights that if non-conservative forces like friction are present, energy conservation would not apply.
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With reference to the attached "energy versus distance graph" of two particles;

a. What minimum speed (m/s) does a 100 g particle need at point A to reach point B?

b. What minimum speed (m/s) does a 100 g particle need at point B to reach point A?

Thank you.
 

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Use conservation of energy. First find the minimum kinetic energy needed to go from A to B, then get the speed from that.
 
Galileo said:
Use conservation of energy. First find the minimum kinetic energy needed to go from A to B, then get the speed from that.

In order to find the minimum kinetic energy, I think I have to find the total work done referring to a "Force vs Distance" graph. But, how can "Force" be found from a graph which is not linear?
 
Work = \int F dx

Is this gravitational potential? In that case, its conservative, and you can ignore anything but the starting and ending points. You lost 2 Joules of PE to get from A to B, so you gained 2 Joules of KE.

KE = 1/2 mv^2

2 = 1/2 (100g) v^2
 
In one dimension, any position dependent force is conservative (the potential (or total?) energy is already given as a function of the position).
 
Isnt "position dependant force" part of the definition of "conservative force"? Say there was a resistance factor such as friction, the energy wouldn't be conserved then.
 
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