Minimum-uncertainty wave function -- contradiction?

Happiness
Messages
686
Reaction score
30
The following equation (5.122) is the minimum-uncertainty wave function, which is a Gaussian wave packet. Since it is Gaussian in ##x##, we may get ##\Delta x## directly from the ##\sigma## of the Gaussian distribution: ##(\Delta x)^2=\frac{\hbar^2}{2(\Delta p_x)^2}##. We have ##\Delta x\Delta p_x=\frac{\hbar}{\sqrt2}##, which contradicts the fact that the wave function has minimum uncertainty, ie., ##\Delta x\Delta p_x=\frac{\hbar}{2}##.

Derivation of (5.122):
Screen Shot 2015-12-23 at 5.08.19 am.png

Screen Shot 2015-12-23 at 5.08.42 am.png


Gaussian distribution:
Screen Shot 2015-12-23 at 5.09.04 am.png
 
Physics news on Phys.org
You should first calculate ##|\psi(x)|^2## and then extract ##\Delta x## from there, not from ##\psi(x)##
 
  • Like
Likes bhobba and Happiness
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. Towards the end of the first lecture for the Qiskit Global Summer School 2025, Foundations of Quantum Mechanics, Olivia Lanes (Global Lead, Content and Education IBM) stated... Source: https://www.physicsforums.com/insights/quantum-entanglement-is-a-kinematic-fact-not-a-dynamical-effect/ by @RUTA
If we release an electron around a positively charged sphere, the initial state of electron is a linear combination of Hydrogen-like states. According to quantum mechanics, evolution of time would not change this initial state because the potential is time independent. However, classically we expect the electron to collide with the sphere. So, it seems that the quantum and classics predict different behaviours!
Back
Top