Minimum Velocity only given distance

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To determine the minimum velocity required for a soccer ball to travel 65 meters, the problem implies that the ball must be kicked at an angle above the horizontal. The optimal launch angle for achieving maximum range is 45 degrees, which minimizes the required initial velocity. Using the range equation, the minimum velocity can be calculated as V_min = √(R * g), where R is the distance and g is the acceleration due to gravity. The discussion highlights that while no angle is specified, the problem suggests an implied angle for calculation purposes. Understanding these principles is crucial for solving similar projectile motion problems effectively.
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Minimum Velocity only given distance!

Homework Statement


A soccer ball is kicked by a goalie to a position that is 65 meters down field. What is the minimum velocity necessary to achieve this feat?


Homework Equations


v2=vf2+2a(x-xo)


The Attempt at a Solution


v2=02+2a(65m)
 
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Assuming no air resistance, the velocity required will be a minimum what the launch angle is 45 degrees above the horizontal. Use the range equation.
 


But no degree angle is specified, does it still have to be 45 degrees? you can still kick a ball and have it roll horizontally
 


True; I thik the statement of the problem implies that the ball is kicked at some angle above the horzontal and when it returns to the ground, it has convered a horizontal distance of 65m.
 


But to use an angle you need an initial velocity, no? None is specified. My professor said that this problem was very difficult and had a trick to it. There's a part b) that says "if it was kicked at 50 degrees instead" where would the ball land?
that might be the clue, so perhaps there's an implied angle?
 


Well, how about this. The range equation is

R = \frac{V_{0}^{2} sin 2\theta}{g}

If you solve the equation for Vo and differentiate the result with respect to theta (dVo / dtheta), set it equal to zero and solve for theta, you get 45 degrees. That proves that the min speed for a given range occurs when theta is 45 degrees.

If you then solve the range equation for Vo and substitute 45 degrees,

(V_{0}) min = \sqrt{R g}
 
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