Missing a Factor of 2 in a Poynting Vector Verification

  • Context: Graduate 
  • Thread starter Thread starter the-brammo
  • Start date Start date
  • Tags Tags
    Poynting vector Vector
Click For Summary
SUMMARY

The discussion centers on the verification of the Poynting theorem in the context of a fat wire carrying a constant current I, with a narrow gap forming a parallel-plate capacitor. A participant identified a discrepancy, specifically a factor of 2 in the derivation related to the divergence of the Poynting vector in cylindrical coordinates. The correct application of the divergence formula, particularly for a vector field with a radial component, confirms that the divergence of the vector field results in the factor of 2, resolving the initial confusion.

PREREQUISITES
  • Understanding of Poynting theorem in electromagnetism
  • Familiarity with cylindrical coordinates and vector calculus
  • Knowledge of divergence operations on vector fields
  • Basic principles of electric current distribution in conductors
NEXT STEPS
  • Study the derivation of the Poynting vector in cylindrical coordinates
  • Learn about divergence and curl operations in vector calculus
  • Explore electromagnetic theory related to parallel-plate capacitors
  • Investigate applications of the Poynting theorem in practical scenarios
USEFUL FOR

Students and professionals in physics, electrical engineering, and applied mathematics who are working with electromagnetic theory and vector calculus, particularly those focused on the Poynting theorem and its applications.

the-brammo
Messages
5
Reaction score
0
The question reads:

A fat wire, radius a, carries a constant current I, uniformly distributed over its cross section. A narrow gap in the wire, of width w << a, forms a parallel-plate capacitor.

I have drawn a red box at the bottom of the page where the Poynting theorem is supposedly verified - however it seems to be a factor of 2 out. I am happy that the derivation for uem is correct, it must be something to do with the very last line. Could someone please point me in the right direction, excuse the pun.

Poynting.png
 
Last edited:
Physics news on Phys.org
You should be careful about taking the divergence in cylindrical coordinates.
 
Is this a hint? I know there are some steps are missing, does a factor of two comes out when the divergence of s is taken in cylindrical coordinates?
 
the-brammo said:
Is this a hint? I know there are some steps are missing, does a factor of two comes out when the divergence of s is taken?

Yes, it was a hint. The divergence of a vector field with only a radial component is given by \nabla \cdot (A_s\hat{s})=\frac{1}{s}\frac{\partial}{\partial s}(sA_s).

So in your example ## A_s =s## and the divergence becomes

\nabla \cdot (s \hat{s})=\frac{1}{s}\frac{\partial}{\partial s}(s^2)=2.
 
Thanks so much, this answers my question perfectly.
 

Similar threads

  • · Replies 14 ·
Replies
14
Views
3K
Replies
26
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
11K
  • · Replies 1 ·
Replies
1
Views
5K
  • · Replies 0 ·
Replies
0
Views
2K