Which Molecules Exhibit Paramagnetism: Be2, B2, C2, or N2?

AI Thread Summary
The discussion focuses on identifying which of the molecules Be2, B2, C2, or N2 exhibits paramagnetism, with the key point being the assumption that 2s-2p mixing is not operative. Participants clarify that paramagnetism is associated with the presence of unpaired electrons, and molecular orbital theory is suggested as a method for analysis. There is confusion regarding the meaning of "2s-2p mixing is not operative," with some interpreting it as a lack of hybridization. Ultimately, the consensus is that C2 is the paramagnetic species among the options provided. Understanding molecular orbital theory is essential for determining the magnetic properties of these molecules.
Raghav Gupta
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Homework Statement


Assuming 2s-2p mixing is not operative, the paramagnetic species among the following is
1. Be2
2. B2
3. C2
4. N2

Homework Equations


NA

The Attempt at a Solution


Not able to understand the statement "2s -2p mixing is not operative".
Can you help?
Paramagnetism is a specie having unpaired electron.
How to relate it here?
 
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You can try molecular orbital theory.
 
mooncrater said:
You can try molecular orbital theory.
What is that statement 2s and 2p is not operative meaning?
 
[What I think] 2s-2p mixing is not operative may mean that hybridization is not done (which is a vsepr concept).
 
mooncrater said:
[What I think] 2s-2p mixing is not operative may mean that hybridization is not done (which is a vsepr concept).
Got it, thanks the answer C2
 
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