Mixing different temperatures of water ?

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To find the final temperature when mixing 1 liter of 20 degrees C water with 2 liters of 40 degrees C water, use the principle of conservation of energy, where the heat lost by the hot water equals the heat gained by the cold water. The equation Q = mcΔT can be applied, where Q is the heat energy, m is mass, c is specific heat capacity, and ΔT is the change in temperature. By setting the heat exchange equations for both water masses equal to each other, you can solve for the final temperature T. The final temperature will be a weighted average based on the volumes and temperatures of the two water bodies. This method provides a straightforward solution to the problem.
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"What would be the final temperature if you mixed a liter of 20 degrees C water with 2 liters of 40 degrees C water?"

My teacher assigned us several problems like these without bothering to explain them. I have a hunch that they are embarrassingly simple to complete, but I know not how to find the solutions. The only equation we've been given to this point is Q = mcΔT.

ANY help would be appreciated. Thanks in advance.
 
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Q is the heat energy. The amount of heat coming out of the hotter water is equal to the amount of heat going into the cooler water. Suppose the final temperature is T (somewhere between 20 and 40 degrees). Find the change in heat for each mass of water and equate them. Then solve for T.
 

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