Mixing problem involving 3 inlets and 2 outlet pipes

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SUMMARY

The discussion focuses on solving a mixing problem involving three inlet pipes and two outlet pipes. It is confirmed that the total flow rate can be calculated by summing the rates of the inlet pipes, but concentrations cannot be simply added. Instead, the total mass flow rate of the substance must be calculated by multiplying the flow rate of each inlet by its respective concentration. For example, a pipe with a flow rate of 3 L/s and a concentration of 10 g/L contributes 30 g/s, while a 5 L/s pipe with a concentration of 5 g/L contributes 25 g/s, resulting in a total of 55 g/s of the substance entering the system.

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tin llenaresas
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help!
how do we solve a mixing problem involving 3 inlet pipes and 2 outlet pipes?is it okay to just add up the 3 rates of input as well as their respective concentrations?
all the sample problems i have encountered involves only 1 inlet and one outlet pipe..
 
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You start by actually explaining the problem! You could have could have one pipe that goes back to the tank itself with two additional inlet pipes and one additional outlet or any variation on that.

Do you have a single tank with 3 pipes coming in and two pipes going out? If that is the case, then, yes, you can treat that as a single with the sum of the inputs. But be careful about how you sum that- you can't just add the concentrations. You have to sum the amount of "substance" that comes in every second. For example, if you have one pipe bringing in a solution at 3 L/s, with concentration 10 g/L of salt and a second pipe bringing in a solution at 5 L/s with concentration 5 g/L of salt, then the first pipe will bring in (3 L/m)(10 g/L)= 30 g/s and the second will bring in (5 L/s)(5 g/L)= 25 g/s. The two pipes will bring in a total of 30+25= 55 g/s. That's the information you need to set up your equation.
 

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