Model a rigid body made of two points linked by a rigid bar

Click For Summary

Homework Help Overview

The original poster is seeking assistance in modeling the dynamics of a two-point mass system that becomes a rigid body upon collision. The scenario involves two masses in a two-dimensional plane, which move with different speed vectors until they collide and stick together, forming a rigid body.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the nature of point masses and the implications of treating the system as a rigid body after collision. Questions arise regarding the forces acting on the system post-collision, including tension and binding forces. There is also consideration of momentum and angular momentum conservation.

Discussion Status

The discussion is ongoing, with participants exploring various interpretations of the forces involved in the system after the collision. Some guidance has been offered regarding the conservation of momentum and the nature of forces acting on the masses, but there is no explicit consensus on the exact forces or their calculations.

Contextual Notes

Participants note the absence of specific details about the forces acting on the particles prior to the collision, leading to assumptions about their free movement. The discussion includes considerations of how the system behaves once the rigid bar is introduced.

cicciolo
Messages
2
Reaction score
0
Hi all!

I need help..:)

I need to model the dynamic of this system:

I'm in the plane (2-dimensions).
There are two points (with m1 and m2 masses) free to move with different speed vectors (in module and direction).
At some point, when the distance between them is d, the two points became a rigid body (as if between them there is a rigid bar which joins them) through a completely inelastic collision.

What are the forces acting on this system?

I hope you can help me!
Thank you in advance :)
 
Physics news on Phys.org
Welcome to PF.

IRL there is no such thing as a point mass.
But you can model a lot by treating an object as though all it's mass were concentrated at it's COM - if the COMs approach close enough, then the actual objects may collide and do all kinds of things. In your case, they stuck together. So you have some sort of adhesion.

Some of the energy in the collision went into joining them together and it is going to take some effort to separate them again. Without more details the exact nature of the sticking forces cannot be ascertained.

Imagine two air-hocky pucks with velcro or double-sided tape around their rims. They'd behave much as described ... free to move in 2D on the air-table but get close enough they behave as a single rigid body.
 
You know the speed of each of the two particles at the time they "connect" so you know momentum and angular momentum of each and so momentum and angular momentum of the system. Those will be conserved.
 
HallsofIvy said:
You know the speed of each of the two particles at the time they "connect" so you know momentum and angular momentum of each and so momentum and angular momentum of the system. Those will be conserved.

So what are the forces involved in the system after the collision?
I think every particles have two forces each:
1) F1 = m*a
2) F2 = binding force directed on the "bar" joining the two particles

So, every particles will have F = F1 + F2.

I'm doing it right?
 
If the system is accelerating then there will be a translating force as you say - and there will be something analogous to tension. If you model the system as two point masses joined by a massless, rigid, 1D, rod - then tension will be pretty much right. The rigid bar has to resist compressing and stretching.

Hit it off-center and you can describe it as having a translating force and a torque.
If the masses are small balls rather than points then it could also have a torque about the long axis.

If you'd just set things in motion, then, after the collision, the composite object will likely be spinning - there will be a centripetal force balanced by tension in the rod.
 
cicciolo said:
So what are the forces involved in the system after the collision?
I think every particles have two forces each:
1) F1 = m*a
2) F2 = binding force directed on the "bar" joining the two particles

So, every particles will have F = F1 + F2.

I'm doing it right?
In your original post, you said nothing about forces acting on particles- I assumed that they were moving freely without forces. Of course, the instant the "bar" is put in place, there will be forces acting along the bar but I see no reason to calculate that force. Just use the fact that the two points and bar, as a whole will have momentum, and angular momentum about any point, equal to the system as a whole before the "bar" appears.
 

Similar threads

  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K
Replies
16
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K
Replies
7
Views
3K
Replies
4
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
Replies
12
Views
3K
Replies
11
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K