Modeling a power as sum of combination

AI Thread Summary
The discussion revolves around modeling the equation 3^n = summation (from i=0 to n) of (n choose i)*(2^i) using a real-life example. The user attempts to illustrate this by considering a scenario with 3 boxes and n items, specifically using 5 items to demonstrate the selection process. However, they struggle to connect their example to the right side of the equation. The conversation highlights the challenge of translating combinatorial concepts into a coherent model. Ultimately, the user seeks guidance to refine their approach and better understand the relationship between the two sides of the equation.
johnhaddad
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Homework Statement



I am trying to come up with a logical explanation (using an example from real life modeled in Combination and/or Permutation) to show that 3^n = summation (from i=0 to n) of (n choose i)*(2^i). In other words, I am trying to pose a combinatorial/selection/combination question that then can be modeled as both sides of the equation.

Homework Equations



Combinations and Permutations.

The Attempt at a Solution



My trial is that 3^n could be modeled as having 3 boxes and we are placing n items in it (eg. balls). So, if we pick n=5, it is as selecting 3 balls to put in box one, then returning them, then selecting 3 balls to put in box 2, then returning..etc while the order of selection is "don't care". However, I still can't show how that translates into the right side of the equation. Any help or pointers?
 
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This is a half-baked idea, see whether you can make anything of it. I have not thought it through, though, not thoroughly. :smile: (Really, I haven't.)

You have discovered a strange mutant strain of yeast cell, here's a slide specimen I prepared -> :bugeye:

Each cell continuously grows in size (diameter) during the period of your study, and on a weekly basis each cell produces a pair of tiny but reproductively-mature offspring. This means the population triples in size every week. You happen to start with an initial population of just 3 cells.

With this scenario, you behold an ever-increasing range of sizes in your yeast culture, with the original 3 always largest in diameter, followed by their first daughters comprising the 6 next largest, followed by 18 same-sized cells (being a mix of daughters and grand-daughters of the original trio), etc.

After 12 weeks, determine how many of these cells populate your laboratory. :smile:
 
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...

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