Modification to metal sphere problem

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    Metal Sphere
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The discussion revolves around a problem involving a metal sphere with a radius of x, surrounded by a conducting shell with inner radius y and outer radius Z, carrying a total charge of 4 microcoulombs. The task is to find the electric field between the outer surface of the metal sphere and the inner radius of the conducting shell. A Gaussian surface is necessary for this calculation, as it helps apply Gauss's law effectively. The inner sphere has a charge of 1 microcoulomb, and the electric field can be determined using the formula derived from Gauss's law. The outer shell does not contribute to the electric field in this region due to the absence of charge between the inner and outer surfaces.
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This problem is somewhat similar to the one I had posted yesterday.

There is a metal spehre, radius=x, that it surrounded by a conducting shell (also spherical) that has an inner radius=y and outer radius=Z. the total charge is 4 micro Coloumbs--> 1 micro Coloumb on the inner sphere, and the rest is distributed in the shell

1)Find electric field between the outer surface of the metal sphere and the inner radius of the conducting shell.

Would I need to take a Gaussian surface between the outer surface of the metal sphere and inner radius of the conducting shell? And also, how would I find the surface charge density on the inner and outer surfaces of the conducting shell?
 
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Assuming that you have no induction and uniform chage density, the outer shell will not contribute to the electric field, since it has no charge between it and inner shell. You simply have q_{in} = 1\mu C, and by Gauss's law for a spherical shell
\int \vec{E}.d\vec{A} = \int EdA = E \int dA = E(4 \pi r^2) = \frac{q_{in}}{\epsilon_0}, which will yield E(r).
 
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