Molarity of HOAc = (1.1544 x 10^-2 mol NaOH) / (0.02132 L vinegar)

[asimon2008]

Homework Statement

A student performing this experiment tirates 22.32 mL of vinegar with 0.5172 M NaOH. The initial NaOH buret reading is 1.18 mL and the final NaOH buret reading is 21.35 mL. What is the molarity of HOAc in the vinegar sample?

Homework Equations

The Attempt at a Solution

(22.32) mL) (1L/1000 mL) (0.5172 mol/L)= 1.1544 x 10^-2 mol NaOH

 

[Borek]

To calculate moles of NaOH you need volume of NaOH solution. 22.32 mL was volume of acetic acid.

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[symbolipoint]

(moles of sought compound) = (moles of titrant compound), if their mole ratio for the reaction is one to one;
Also, for same ratio, M_s*L_s=M_t*L_t,
where subscripts are s for sought and t for titrant.