Moment of Inertia Ball and Stick Collision

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Homework Help Overview

The problem involves a mass dropped from a height onto a pivoted stick, requiring analysis of the moment of inertia and the conservation of momentum and energy during the collision. The subject area includes dynamics, rotational motion, and energy conservation principles.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the use of kinematic equations to find the speed of the mass before impact and explore the relationship between linear and angular momentum. There are attempts to relate angular momentum before and after the collision, as well as considerations of energy conservation.

Discussion Status

Some participants have offered guidance on the relationships between linear and angular quantities, while others express confusion regarding the calculations and the implications of energy conservation. Multiple interpretations of the problem setup and equations are being explored.

Contextual Notes

There is mention of potential confusion due to the participants' varying familiarity with the concepts, as well as the need for clarification on the equations relating linear motion to rotational motion.

tachu101
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Homework Statement


A mass is dropped from height (h) onto one end of a stick of mass (m) and of length (l) pivoted around the opposite end. The moment of inertia of the stick is 1/3ML^2. Upon collision the mass adheres to the stick.

a. Find speed of mass just before impact
b. Find angular speed of the system immediately after impact
c. Find linear speed of the mass (m) at its lowest point (when stick is vertical)
d. Determine the mechanical energy lost as a result of the collision.

Homework Equations


Conservation of angular momentum
angular kinematics equations

The Attempt at a Solution



For the first part I think I found easily with vf^2=Vo^2+2ah which will get you vf=(2ah)^1/2
The last three parts I am very confused about. I have that Io wo=If wf The last part I would think I would use the kinetic energy at the start and at the bottom.
 
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Remember the relationship between [tex]\omega[/tex] and velocity [tex]v = r \omega[/tex] also remember in this incident the complete momentum equation entails linear momentum so

[tex]mv_{i} + I \omega_{i} = mv_{f} + I \omega_{f}[/tex]

remember there is no initial rotational momentum

I am a tad rusty right now since its been over 2 months since I've last seen this stuff (vacation lol)

I know for sure this model holds for conservation of energy though

comment on and/or let me know how it works out

Edit: remember your [tex]v_{f}[/tex] (from kinematics) = [tex]v_{i}[/tex] (in the momentum equation)
 
Does Mo*Vo= I*Wfinal and then is I=(1/3)(2M)(L^2) this will cause the angular speed to be really complicated looking (3/2L^2)*(2gh)^(1/2) and is no mechanical energy lost in the system?
 
djeitnstine said:
I know for sure this model holds for conservation of energy though

Also, I am having trouble finding the equation for linear motion compared to rotational, does anyone have a link to the trig equation?
 
v = rw
linear velocity = radius x angular speed
 
tachu101 said:
Does Mo*Vo= I*Wfinal and then is I=(1/3)(2M)(L^2) this will cause the angular speed to be really complicated looking (3/2L^2)*(2gh)^(1/2) and is no mechanical energy lost in the system?
What's the angular momentum of the system before the collision?
What's the rotational inertia of the system once the ball attaches to the stick?
Use this to find the rotational speed just after the collision.

What's the energy of the system just before the collision? Just after the collision?
 

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