Moment of inertia of a right triangle

  • Thread starter munther
  • Start date
  • #1
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in my hw the question wants from me to find the moment of inertia of
right triangle with the y-axis

as shown in the attatchment

note: the mass of the plate is 1 kg

i found the y coordinate of the center of mass of the plate it is 5/3
and i supposed it is the r

so the inertia will be mr^2
=1*(5/3)^2
=25/9
=2.77777 kg m^2

is that right??
 

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Answers and Replies

  • #2
radou
Homework Helper
3,115
6
If you're calculating the moment of inertia with respect to the y-axis, then it doesn't look right.
 
  • #3
11
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Thank you >
but Why??

can you give me a hint??
 
  • #4
1,357
0
i found the y coordinate of the center of mass of the plate it is 5/3
and i supposed it is the r
I think it would be better for you to show us how you found that. Also, why do you suppose it is "the r"?
 
  • #5
11
0
I think it would be better for you to show us how you found that. Also, why do you suppose it is "the r"?

i found it from the first part of the question
 
  • #6
1,357
0
i found it from the first part of the question
Now that you found it, please post it.
 

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