Momentum: A bullet passing through a wooden block on a frictionless surface

AI Thread Summary
A wooden block with a mass of 1 kg is struck by a 2 g projectile traveling at 300 m/s, and the problem involves calculating the final velocities of both after the collision. The initial kinetic energy of the projectile and the work done on the block are key components in the energy balance equation. The conservation of momentum must be applied correctly, accounting for the momentum before and after the projectile passes through the block. The equations provided for energy and momentum conservation are confirmed to be correct, and the user is encouraged to solve the resulting system of equations. The discussion emphasizes the importance of correctly applying physics principles to arrive at the final velocities.
mmoadi
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Homework Statement



A wooden block with a length of 10 cm and a mass of 1 kg lies on an icy plane. A projectile with mass of 2 g hits the wooden block with velocity of 300 m/s and breaks through its center of gravity. How much are the final velocities of the wooden block and the projectile? While moving through the wooden block, the projectile worked on it with a force of 500 N. This is a frictionless system.

Homework Equations



KE= ½ mv²
p=mv

The Attempt at a Solution



KE= F*d=50 J
KE= ½ m(1)v(final)² → v(1-final)²= 2KE/ m(1)
v(1-final)= 223.6 m/s

Conservation of the momentum:
m(1)v(1-initial) + m(2) v(2-initial) = m(1)v(1-final) + m(2) v(2-final)
v(2-final)= [m(1)v(1-initial) + m(2) v(2-initial) - m(1)v(1-final)] / m(2)
v(2-final)= 0.15 m/s

Is my approach to the problem and calculations correct?
Thank you for helping!
 
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Your energy balance equation is incorrect. The initial kinetic energy of the bullet KE0, which you can calculate is a certain number of Joules. That number of Joules is divided into three parts

1. Work done by bullet on block (F*d)
2. Final kinetic energy of block.
3. Final kinetic energy of bullet.

Your momentum conservation equation is also incorrect.

Pbefore=Momentum of bullet only
Pafter=Momentum of bullet + momentum of block

"Before" means before the bullet hits the block; "after" means after the bullet has made it through.
 
So, if I write it like this:

½ m(1)v(1-initial)²= ½ m(1)v(1-final)² + ½m(2)v(2-final)²+F*d

And

m(1)v(1-initial)= m(1)v(1-final) + m(2)v(2-final)

I have the right equations to work with?

Thank you for helping!
 
Last edited:
Yes, these are the correct equations to start from.
 
OK, but how do I continue.:confused:
I tried to express v(2-final) with the components of the second formula (conservation of the momentum) and insert it into the first formula (KE) but it just got very complicated and weird.:redface:

Can you give me another hint, please?
 
mmoadi said:
OK, but how do I continue.:confused:
I tried to express v(2-final) with the components of the second formula (conservation of the momentum) and insert it into the first formula (KE) but it just got very complicated and weird.:redface:

Can you give me another hint, please?

Weird or no weird, that's exactly what you have to do. There are no other hints. You have to solve a system of two equations and two unknowns and you described the correct way to solve it.
 
Thank you for helping! :smile:
Back to solving my weirdness of equation!:biggrin:
 
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