Momentum After Inelastic Collison

AI Thread Summary
In an inelastic collision, momentum is conserved, meaning the total momentum before the collision equals the total momentum after. For the two hockey pucks, their initial momenta are 35 kg*m/s and 7 kg*m/s, totaling 42 kg*m/s. After they collide and stick together, the combined momentum remains 42 kg*m/s. Although kinetic energy is not conserved in this type of collision, the momentum calculation confirms that the final momentum is indeed 42 kg*m/s. Therefore, the final speed can be determined using the combined mass of the two pucks.
NatalieWise123
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Homework Statement


Two hockey pucks are sliding across the ice in the same direction. One has a momentum of 35 kg*m/s. The other has a momentum of 7 kg*m/s. After the collision, the pucks stick together. What is the momentum of the pucks after the collision?

Homework Equations

The Attempt at a Solution


I'd think you'd just add them together because of the Law of Conservation of Momentum but for some reason I'd imagine they'd slow down after hitting. Is 42 kg*m/s the right answer and if so why?[/B]
 
Physics news on Phys.org
Even though energy is not conserved in an in an inelastic collision,
momentum is conserved.
So write an equation for conservation of momentum and solve for the final speed.
Remember, you now have a final mass of 2 m.
 
Thread 'Collision of a bullet on a rod-string system: query'

Thread 'Collision of a bullet on a rod-string system: query'

In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
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