# Homework Help: Momentum and Impulse

1. Mar 31, 2009

### Black_Hole???

A golfer hits a golf ball of mass 0.045 kg the ball over some short trees. He hits the ball at
an angle of 600 to the horizontal and it travels a horizontal distance (Range) of 60.0 m in a
time of 8.00 s. The golf club of mass 0.60 kg is in contact with the ball for a time of 2.40
ms.

(a) What is the average impulsive force on the golf ball?

(b) What is the average impulsive force on the golf club?

(c) What is the change in momentum of the golf club?

ANSWER: Change in Momentum = ___________ ______

Answers are suppose to be A1) 281.25 A2) -281.25 A3) -.675 kgm/s

2. Mar 31, 2009

### rl.bhat

Don,t say bump
Open the book. Find the relevant formula. Show your effort.

3. Mar 31, 2009

### Black_Hole???

refresh. Just putting the forums on my subscription. not trying to get people to do it for me

4. Mar 31, 2009

### Black_Hole???

Ok i know the formula that i need to use but i don't know how to solve for velocity of the ball.

What i would use though if i had the velocity of the ball would be.

Impulse = (p2-p1)/(t2-t1)

P = mv which is finding momentum.

I have an idea in which to find the velocity and that would be a free falling problem. But i can't get anything to work.

Thanks

5. Apr 1, 2009

refresh

6. Apr 1, 2009

refresh

7. Apr 1, 2009