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Momentum Issues

  • Thread starter AlKaiser
  • Start date
3
0
1. The problem statement:
A 98 kg man lying on a surface of negligible friction shoves a 86 g stone away from himself, giving it a speed of 4.5 m/s. What speed does the man acquire as a result?




2. Homework Equations :
Pi = Pf
M1V1 + M2V2 = M1V1 + M2V2




3. The Attempt at a Solution :

I've tried the formula above, and I got this far:

98 x 0 + 0.086 x 0 = 98 x X + 0.086 x 4.5
0 = 98X + 0.387
-0.387 = 98X
-0.387/98 = X
X = -0.00394897959 m/s


That's what I got. I have a feeling that I've done something wrong. The online Assignment system is telling me my answer is wrong, so what am I doing wrong? Have I missed something? All help is greatly appreciated :D
 
…M1V1 + M2V2 = M1V1 + M2V2…

When you are substituting the velocity into the equation, the left side of the equation. The equation normally should look more like this:

[tex]m_a*u_a-m_b*u_b=m_a*v_a+m_b*v_b[/tex]

By the way, I state "u" as the initial velocity of the object(s), and "v" as the final.
 
133
0
If you're taking the direction of the stone's velocity to be positive, the other has to be negative since its in the opposite direction. ;)
 

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