Momentum of ball bouncing off wall

AI Thread Summary
The discussion centers on calculating the change in momentum of a racquet ball during a perfectly elastic collision with a wall. The ball, with a mass of 0.247 kg and an initial velocity of 12.4 m/s at a 32° angle, rebounds at the same angle after contact. The change in momentum can be determined by considering the momentum components; the parallel component remains unchanged while the perpendicular component reverses direction. Participants suggest using conservation of kinetic energy and the relationship between force, change in momentum, and time to solve the problem. The focus is on applying the principles of momentum as a vector quantity to derive the solution effectively.
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Homework Statement


A racquet ball with mass m = 0.247 kg is moving toward the wall at v = 12.4 m/s and at an angle of θ = 32° with respect to the horizontal. The ball makes a perfectly elastic collision with the solid, frictionless wall and rebounds at the same angle with respect to the horizontal. The ball is in contact with the wall for t = 0.063 s.


Homework Equations


What is the magnitude of the change in momentum of the racquet ball?


The Attempt at a Solution


I found the initial P already and am not sure if I should use the (delta)P= F(net)* (delta)t and use 1-d kinematics to find acceleration or how exactly to begin.
 
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Since the collision is assumed to be perfectly elastic, try using conservation of KE.
 
Then find the change in momentum.
 
Momentum is a vector quantity. The component of momentum parallel to the way will not change. The component of momentum perpendicular to the way is multiplied by -1.
 
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