Momentum of carts of different masses

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To ensure both carts hit the ends of the track simultaneously after an explosion, a mass of 1.54 kg must be placed on cart X. The momentum conservation equation indicates that the momentum of cart X (px) equals the momentum of cart Y (py) only if the mass on cart X equals the mass on cart Y. The kinetic energy of cart X (Ex) is not equal to that of cart Y (Ey), as Ex is calculated to be 2.8575vy² while Ey is 1.92vy². The analysis concludes that the only correct statement regarding momentum is px = py, while other statements about kinetic energies and momenta are deemed incorrect. This discussion highlights the importance of understanding momentum and energy conservation in explosive interactions.
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Homework Statement



The drawing below shows two laboratory carts (each has a mass of 1.0 kg) X and Y in contact with a compressed exploder spring between them. The mass on cart Y is 2.84 kg, distance A is 12 cm, distance B is 18 cm. What mass must be placed on cart X, such that after the explosion both carts will hit the ends of the track at the same time?

After the explosion has taken place, which of the following statements regarding the kinetic energies, EK, and the magnitudes of the momenta, pi, are correct or incorrect? (Note: The subscripts x and y refer to the carts, not the direction along x or y.)
Ex = 2/3 Ey
px > py
px = py
Ex < Ey
px = py/2


Homework Equations



Final momentum = inital momentum = 0

MxVx + MyVy = 0

T = d/v

The Attempt at a Solution



z = unknown mass on cart x
(1 + z)Vx + (1.00 + 2.84)Vy = 0

T= 12/Vy = -18/Vy so Vx = -18/12 Vy

(1+z) *-18/12 Vy + 3.84 Vy = 0

Vy[(1+z)*-18/12 + 3.84] = 0

-18/12 + -18/12 z + 3.84 = 0

-1.5Z = -2.34

Z = 1.54 kg


After the explosion has taken place, which of the following statements regarding the kinetic energies, EK, and the magnitudes of the momenta, pi, are correct or incorrect? (Note: The subscripts x and y refer to the carts, not the direction along x or y.)
Correct Incorrect Ex = 2/3 Ey
incorrect energy should be the same
Correct Incorrect px > py
not sure: depends on answer in part 1 because p = mv
Correct Incorrect px = py
Incorrect unless Mx = 2.84
Correct Incorrect Ex < Ey
Incorrect energy should be the same
Correct Incorrect px = py/2
 
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confused by this part:

"T= 12/Vy = -18/Vy so Vx = -18/12 Vy"

Do you mean 12/Vy = -18/Vx?
 
yea.. and from that you can derive that Vx = (-18/12)Vy
 
ttk3 said:
yea.. and from that you can derive that Vx = (-18/12)Vy

ok... So Ex = (1/2)(1+1.54)vx^2 = 1.27(1.5vy)^2 = 2.8575vy^2

Ey = (1/2)(1+2.84)vy^2 = 1.92vy^2

so it seems like out of all the choices the only right one is px = py.

BTW Ex is not the same energy as Ey.
 
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