1. The problem statement, all variables and given/known data After winning a prize on a game show, a 72 kg contestant jumps for joy. A. If the jump results in an upward speed of 2.1 m/s, what is the impulse experienced by the contestant? b. 0.0 c. 75.6 kg.m/s d. 151.2 kg.m/s e. 226.8 kg.m/s B. Before the jump, the floor exerts an upward force of magnitude mg on the contestant. What additional average upward force does the floor exert if the contestant pushes down on the floor for 0.36 s during the jump? a. 0.0 b. 210.0 N c. 420.0 N d. 630.0 N 2. Relevant equations P=mv delta p= f*delta t 3. The attempt at a solution For part A: Since the contestant is on the ground initially, he has zero momentum, and after he jump his final speed is 2.1m/s. P=mv, I calculated 151.2 kg*/s as his change in momentum. However, the answer for this part should be 75.6kg*m/s... For part B I used the impulse divide by time to get the average force, and the value is 420N. The answer is 420 N but I thought that I should use mg substruct 420N to get the "additional force" Any suggestions please?