Most powerful test involving Poisson

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    Poisson Test
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Homework Statement


The number of sales made by a used car salesman, per day, is a Poisson random variable with parameter \lambda. Given a random sample of the number of sales he made on n days, what is the most powerful test of the hypothesis Ho: p = 0.10 versus Ha: p = 0.25, where p is the probability he makes at least one sale (per day)?


Homework Equations


f\left(x;\lambda\right) = \frac{e^{-\lambda}\lambda^{x}}{x!}


The Attempt at a Solution


I applied the single likelihood ratio test which Rejects Ho if \lambda \leq k which I found equivalent in saying to reject Ho if \sum Xi \leq k' where k' is given by P\left[\sum Xi \leq k'\right] = \alpha
But it seems not correct since the hypotheses involve p and not the parameter \lambda. Please help me solve this problem.
 
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what are k & k'?

just a few ideas to get you started:
- first I'd look at how p is related to lambda
- then i would look at the likelihood of each hypothesis
- consider how to derive the power of the test
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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