Calculating Distance and Time for Meeting at Constant Velocities

In summary: Yes, you are correct. And to answer the original question, in summary, the restaurant is located 2 blocks away from your building.
  • #1
Manh
62
0
You and your friend are in building four equal-length blocks apart, and you meet for lunch. Friend is 1.2 m/s and you are 1.6 m/s. The restaurant is between the two building and you and your friend will arrive at the same instant if both of you leave the buildings at the same instant. In blocks, how far from your building is the restaurant?

Can anyone guide me how to solve this problem? Thanks!
 
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  • #2
Manh said:
You and your friend are in building four equal-length blocks apart, and you meet for lunch. Friend is 1.2 m/s and you are 1.6 m/s. The restaurant is between the two building and you and your friend will arrive at the same instant if both of you leave the buildings at the same instant. In blocks, how far from your building is the restaurant?

Can anyone guide me how to solve this problem? Thanks!
Let's say that you travel a distance, x. What distance does your friend travel?
 
  • #3
The problem only provide me blocks but it does not provide me distance x? Therefore, it's the problem!
 
  • #4
Manh said:
The problem only provide me blocks but it does not provide me distance x? Therefore, it's the problem!
Distance for this problem is in units of blocks.

I repeat: Let's say that you travel a distance, x. What distance does your friend travel?
 
  • #5
I think my friend travel in 4x? Can you give me second hint?
 
  • #6
Manh said:
I think my friend travel in 4x? Can you give me second hint?
No way is it 4x. Can't give much bigger hint than I gave.

Total distance traveled by the two of you is 4 (blocks).

You travel x (blocks). How far does your friend travel?
 
  • #7
Oh, is it 4 - x?
 
  • #8
Manh said:
Oh, is it 4 - x?
Yes it is.

If each of you walks for a time, t, what distance does each of you walk?
 
  • #9
So, my friend walk 4 - x and I walk x.
 
  • #10
Manh said:
So, my friend walk 4 - x and I walk x.
You already gave that answer.

The problem gives a walking speed for each of you. Based on those speeds:
If each of you walks for a time, t, what distance does each of you walk?​
 
  • #11
Do I need the formula v=x/t to find our distances?
 
  • #12
Manh said:
Do I need the formula v=x/t to find our distances?
Solve that for distance.
 
  • #13
The formula of distance is x = v * t. What do I plug in for t when it is not given?
 
  • #14
Manh said:
The formula of distance is x = v * t. What do I plug in for t when it is not given?
but v is given numerically.

just use the variable t.

Do you have much experience with algebra ?
 
  • #15
Oh, I see what I need to do this part now! I will have my answers in a moment.
 
  • #16
I got t=10/7. Is it correct? If so, should I express it in a decimal number?
 
  • #17
Manh said:
I got t=10/7. Is it correct? If so, should I express it in a decimal number?
It may be the correct answer for something.

That certainly isn't the correct answer for what I asked.

There should be two answers, one for you, one for your friend.

If you travel at 1.6 m/s, what distance do you travel in a time of t (seconds) ?

If your friend travels at 1.2 m/s, what distance does your friend travel in a time of t (seconds) ?
 
  • #18
These are my equations:
- My distance: x = 1.6*t
- My friend's distance 4 - x = 1.2*t
4 - 1.6t = 1.2t

From there, I solve for t to plug it back into my distance's equation. Am I correct?
 

1. What is motion at constant velocity?

Motion at constant velocity refers to an object moving at a constant speed in a straight line, with no changes in direction. This means that the object is moving at a steady rate without any acceleration or deceleration.

2. How is constant velocity different from constant speed?

Constant velocity means that an object is moving at a constant speed and in a straight line, while constant speed only refers to the rate at which an object is moving. Constant velocity also takes into account the direction of the motion.

3. What causes an object to have constant velocity?

An object will have constant velocity if the net force acting on it is zero. This means that the forces pushing or pulling on the object are balanced, resulting in a steady motion without any changes in speed or direction.

4. Can an object have constant velocity if it is accelerating?

No, constant velocity and acceleration are two different concepts. An object cannot have constant velocity if it is accelerating, as acceleration involves a change in velocity (speed or direction) over time. However, an object can have a constant velocity if it is accelerating at a rate of zero, meaning its speed remains constant.

5. How is constant velocity represented on a position-time graph?

On a position-time graph, constant velocity is represented by a straight, horizontal line. This indicates that the object is moving at a constant position (no change in distance from the starting point) over time, which means its speed and direction are not changing.

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