Derivation of the Kinematic Equations

AI Thread Summary
A car decelerates from 23 m/s to rest over 85 meters, prompting a discussion on deriving the kinematic equations. The key equation mentioned is v² = v₀² + 2ax, where v is the final velocity, v₀ is the initial velocity, a is acceleration, and x is displacement. Participants clarify that to find acceleration, one can substitute known values into this equation. The conversation also touches on eliminating time from the velocity-time and position-time equations to derive the kinematic equations. Overall, the focus is on understanding and applying the correct kinematic formulas for constant acceleration scenarios.
alexgraham
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A car slows down from 23 m/s to rest in a distance of 85m. what was its acceleration, assumed constant?
a=Δv/Δt x=1/2at^2
i don't know where to start
 
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what is the velocity-displacement formula?
 
v^2=2ax
 
in that equation is v the change in velocity?
 
Ignore this post, it was bad advice!
 
Last edited:
v^2=2ax
 
okay thanks i guess my teacher messed up
 
I'm sorry, I just gave you some bad advice...ignore my first response.
 
I don't know what I was thinking, but yeah you use (final velocity)^2 = (initial velocity)^2 + 2*a*x and just substitute the stuff you know and solve for a.
 
  • #10
Does anyone know how to derive V^2=V0^2+2as

Ratch
 
  • #11
Take the velocity-time equation:
<br /> v = v_{0} + a \, t<br />
and the position time equation:
<br /> x = v_{0} \, t + \frac{1}{2} \, a \, t^{2}<br />
and eliminate time t.
 
  • #12
Ratch said:
Does anyone know how to derive V^2=V0^2+2as

Ratch

Work energy theorem
KEv2-KEv0=mas
 
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