# Homework Help: Motion of a freely falling object

1. Sep 8, 2007

### chom

Hello everyone, I'm new here and a physics noob. I'm doing Physics 024 correspondence via web and my tutor has a (if I'm lucky) a once a week schedule to talk with him. Thought I might have better luck here since I'm on a strict time frame to get this done.
Here goes....

I measured the displacement for each interval of a ball bearing free falling (in a picture in my textbook) next to a meter stick with a strobe light flashing in 0.050 s intervals. From this measurement I calculated the following data:
100mm (length of ruler on page 77)
I then factored the scale by using: 1000mm/100mm (actual length of meter stick)/(length of meter stick on print) = 10mm scale factor

Time(s) 0.050 0.100 0.150 0.200 0.250 0.300 0.350 0.400 0.450 0.500 0.550 0.600

∆d(mm)displacement
Measured for
interval 0.5 4.0 10.0 18.0 29.0 42.5 59.0 77.5 99.0 123.0 150.0 178.5

∆d (cm)actual
Displacement for
interval .50 4.0 10.0 18.0 29.0 43.0 59.0 78.0 99.0 123.0 150.0 180.0

V (cm/s)actual average velocity
For interval 10.0 80.0 200.0 360.0 580.0 860.0 1200.0 1600.0 2000.0 2500.0 3000.0 3600.0

Sorry, the forum wouldn't let me upload my word doc for word 2007 for a proper data table.

To find actual displacement the calculation I used was ∆d(mm) x 10mm(scale factor) = ∆d(mm), then I converted to cm to get the actual displacement for ∆d(cm).

To find actual average velocity I used the calculation: v=(∆d(cm))/0.050s for each interval in question.

Next, I drew a Velocity-Time graph for the motion, I calculated average acceleration using: a=∆v/∆t,
a=3600/0.600 = 6000 = 6.0x10^3cm/s^2
converted to m/s is 6.0x10^1m/s^2 which is very far from the value of g = 9.8m/s^2.

I am fairly new to all of this and any advice to where my error is would be greatly appreciated.

Chom
1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

2. Sep 8, 2007

### learningphysics

Are you sure those displacements over each interval? And not total displacement since t=0?

3. Sep 8, 2007

### chom

So are you saying I should be measuring the displacement of each interval as 0 to d1, d1 to d2, d2 to d3, etc? Instead of total displacement being 0 to d1, 0 to d2, 0 to d3, etc. Maybe that is what my books means "measure the displacement for each interval of time. I was having trouble understanding exactly what it meant. Please verify. Then as far as the t=0 could you elaborate on that a bit more?

4. Sep 8, 2007

### learningphysics

Yes, the displacment should be over each interval... If d1,d2,d3 are positions... that means they are the displacement since t=0...

ie I was asking if d2 is the displacement from t=0 to t2... or the displacement from t1 to t2...

You should be using displacement from t0 to t1... t1 to t2... t2 to t3... etc... because you're calculating the average velocity over that time period... so you should only use displacement over that time period...

5. Sep 8, 2007

### chom

Thank you for the help. That total makes sense. For some reason i was still using the method for making a position time graph. Can't believe it took me that long to figure it out. Anyways, thank you very much.

Chom