Motion problems using antiderivatives

AI Thread Summary
The discussion revolves around solving motion problems using the antiderivative of the velocity function v = 6t - 3t^2. The key tasks include calculating the distance traveled by the object in the first second and the first two seconds, as well as determining the total distance when the object returns to its starting point at t=3. The antiderivative provided, s = 3t^2 - t^3 + c, is a crucial step in finding the displacement. Participants suggest evaluating the difference in position at specific time intervals to find the required distances. The conversation emphasizes understanding the relationship between velocity, position, and time in motion problems.
Nitrate
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Homework Statement



An object moves in a straight line with velocity v = 6t-3t^2, where v is measured in metres per second.
a) how far does the object move in the first sec?
b) how far does the object move in the first two seconds?
c) the object is back where it started when t=3. how far did it travel to get there?


Homework Equations





The Attempt at a Solution



the only bit i got was the anti derivative s=3t^2-t^3+c

help is requested :D
 
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Nitrate said:

Homework Statement



An object moves in a straight line with velocity v = 6t-3t^2, where v is measured in metres per second.
a) how far does the object move in the first sec?
b) how far does the object move in the first two seconds?
c) the object is back where it started when t=3. how far did it travel to get there?

Homework Equations

The Attempt at a Solution



the only bit i got was the anti derivative s=3t^2-t^3+c

help is requested :D

a) should be pretty easy. It's the difference between s when t=1 and s when t=0, isn't it? Try working that out first.
 
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