Motion with Incline: Masses, Acceleration, Tension & Friction | Incline Homework

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SUMMARY

The discussion focuses on a physics problem involving two masses, m1 = 4.0 kg and m2 = 9.0 kg, connected by a string over a frictionless pulley, with m2 sliding down a 40-degree incline. The acceleration of m2 is calculated to be 0.125 m/s² using the distance formula. The tension in the string and the coefficient of kinetic friction between m2 and the incline are also key components of the problem. Participants emphasize the importance of drawing free body diagrams and setting up equations for each mass to solve for the unknowns effectively.

PREREQUISITES
  • Understanding of Newton's second law (Fnet = ma)
  • Knowledge of kinematic equations, specifically the distance formula d = 1/2at²
  • Familiarity with free body diagrams and vector forces
  • Concept of kinetic friction and its coefficient
NEXT STEPS
  • Study the derivation of kinematic equations for different scenarios
  • Learn how to construct and analyze free body diagrams for complex systems
  • Research the principles of tension in strings and pulleys
  • Explore the effects of friction on inclined planes and how to calculate the coefficient of kinetic friction
USEFUL FOR

Students studying physics, particularly those tackling mechanics problems involving inclined planes, tension, and friction. This discussion is beneficial for anyone preparing for exams or working on homework related to dynamics and kinematics.

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Homework Statement



Masses m1 = 4.0kg and m2 = 9.0kg are connected by a light string that passes over a frictionless pulley. As shown in Figure, m1 is held at rest on the floor and m2 rests on a fixed incline of 40 degree. The masses are released from rest, and m2 slides 1.00m down the incline in 4.00s.

Determine a) the acceleration of each mass b) the tension in the string and c) the coefficient of kinetic friction between m2 and the incline.


DSC00508.jpg



Homework Equations


Fnet = ma
distance formula
d = 1/2at^2 when vi = 0


The Attempt at a Solution



Well, I know the acceleration for m2 is 0.125m/s^2 using the distance formula when vi=0.
but then i got stuck at the rest, i tried to find acceleration of m1 but didn't work out at all.

well if i tried
m2gcos - m1g = m2a1+m1a2
(since incline plane i can find fg by m2gCos)
but the problem is, i totally ignore the friction Ff i think...
this is why i come up with answer like 6.8m/s^2 for mass1.

the rest will be wrong if i can't set up a system of equation for #1
i tried, like

m2gCos + Ft = m2a
m1g + (-Ft) = m1a

Ft means force of tension
 
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You need to consider the forces on each mass separately. Remember, force is a vector.

Start by considering just the mass on the incline. Draw a free body diagram. What forces are present? Write out an equation for each direction (take the x direction to be along the incline and the y direction to be perpendicular to the incline).

Now do the same for the other mass. This one is much easier, since there are only forces in one direction.

From this you will get a set of equations that you can use to solve for what you need to find.
 

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