How much work is required to stop a moving block?

AI Thread Summary
To stop a 3kg block moving at 4 m/s, the work done must equal the change in kinetic energy, calculated as 24 Joules. The initial kinetic energy is determined using the formula 0.5 x mass x (final velocity squared - initial velocity squared). A constant friction force of 2 Newtons acting on the block allows for the calculation of acceleration using F=ma, resulting in an acceleration of approximately 0.67 m/s². The approach to solving both parts of the problem is confirmed as correct. Understanding the relationship between work, energy, and forces is crucial in these calculations.
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Homework Statement



a 3kg block moves initially at 4 m/s at t=0 and slides on a horizontal surface... Find the magnitude of word that must be done on the block to bring it to rest

Homework Equations


I believe we must use the equation w=Fs


The Attempt at a Solution



I drew the free body diagram and figured that the we have to find the opposing force and the relative displacement. I am having a hard time getting started with this problem. i know that [F]=[N][m] and =[m]
 
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Work done is equal to the change in kinetic energy.
What is the initial KE?
What is the final KE?
 
okay so i figured that the change in KE=.5 x m x (vf^2-vi^2)
for this problem it would equal 24J
 
Yes. It is correct.
 
There is an extention to the problem:

A constant friction force of 2 Newtons is exerted on the block by the surface find the magnitude of acceleration of the block

So I used F=ma where the force i used was 2 and the mass was 3 so id id

2/3 to find the acceleration which is .66666 is this the right method to answering this question?
 
nm i got the right answer thankyou!
 
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