Multiple variable prediction interval

AI Thread Summary
The discussion focuses on calculating prediction intervals for multiple variable regression, building on the single variable formula. The key adaptation involves replacing the single variable terms with a linear combination of multiple predictors. The standard error is suggested to be substituted with a cross-covariance matrix, and the square root term is adjusted to accommodate vector calculations. The final formulas for mean and specific value intervals are provided, emphasizing the need for matrix equivalents in the calculations. This information is deemed helpful for progressing in understanding multiple variable regression.
Uniquebum
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Hey!

I'm working with some regression related stuff at the moment and i'd need some help with multiple variable prediction interval. Prediction interval for a single variable can be calculated using

PI = \hat{\beta_0}+\hat{\beta_1}x_i \pm t^* s_e \sqrt{1+\frac{1}{n} + \frac{(x_i-mean(x))^2}{S_{xx}}}

where x can be thought as a 1 dimensional vector (or matrix/set) which holds the values x_0, x_1, x_2 and so on. Also, \hat{\beta_0}+\hat{\beta_1}x_i is a linear regression line \hat{y}. Finally, t^* is the t-percentile, s_e is standard deviation, n is the amount of points in the sample and S_{xx} = \sum{(x_i-mean(x))^2} from 1 --> n.

Now what does the equation look like for multiple variable regression?

I'd suppose \hat{\beta_0}+\hat{\beta_1}x_i is easily changed to
\hat{\beta_0}+\hat{\beta_1}x_{0i}+\hat{\beta_2}x_{1i}+\hat{\beta_3}x_{2i}+...
but what do i do with
\frac{(x_i-mean(x))^2}{S_{xx}}
?
 
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I'm sorry you are not generating any responses at the moment. Is there any additional information you can share with us? Any new findings?
 
Uniquebum said:
Now what does the equation look like for multiple variable regression?

I'd suppose \hat{\beta_0}+\hat{\beta_1}x_i is easily changed to
\hat{\beta_0}+\hat{\beta_1}x_{0i}+\hat{\beta_2}x_{1i}+\hat{\beta_3}x_{2i}+...
but what do i do with
\frac{(x_i-mean(x))^2}{S_{xx}}
?
Off the top of my head, I would say that s_e would be replaced by a cross-covariance matrix of the x_{j}s and that the square root would be replaced by a vector where each element is calculated with the square root equation.

PS. Your equations should drop the i subscript where x is now an arbitrary input rather than the sample data point i.

PPS. I don't know which sign of the square root to pick. I think that an authoritative answer to your OP will take more expertise than I have.
 
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You'll find formulae if you look in a book on multiple regression, linear models, or basic multivariate analysis. Essentially you replace the quantity you ask about with the matrix equivalent. If \widehat y is the fitted value from the equation, and \mathbf{x}_0 is the specified value of the predictor, the interval estimate for the mean value of the response is

<br /> \widehat y \pm t \sqrt{\, \hat{\sigma}^2 \mathbf{x}&#039;_0 \left(X&#039; X\right)^{-1} \mathbf{x}_0 }<br />

If you want the interval for the particular value it is

<br /> \widehat y \pm t \sqrt{\, \hat{\sigma}^2 \left(1 + \mathbf{x}&#039;_0 \left(X&#039; X\right)^{-1} \mathbf{x}_0 \right) }<br />
 
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Thanks a lot for the replies. I looked through a couple of books but they only talked about multiple variable regression in too vague manner. This'll help me get forward. Thanks again.
 
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