Multivariable Max and min value problem.

yaho8888
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Homework Statement


find local max min and saddle point.
f(x,y)= sin(x)sin(y), -pi<x<pi, -pi<y<pi

Homework Equations


none

The Attempt at a Solution


fx = cos(x)sin(y)
fy= sin(x)cos(y)

now how do I get the critical points, I know how to get max min and saddle point, but I don't know how to get critical points from this equation. when fx fy = 0, we got the critical point, I know there is (0,0), how do I find the others. I got another points (pi/2,pi/2), (-pi/2,-pi/2). is there more?
 
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What do you mean by "fxfy= 0"? The product? A "critical point" is defined as a point where the function is not differentiable or where the partial derivatives are equal to 0. Since this function is obviously differentiable everywhere, its critical points are where cos(x)sin(y)= 0 and sin(x)cos(y)= 0. Since sin(x) and cos(x) can't be 0 at the same x, you must have either sin(x)=0 and sin(y)= 0 or cos(x)= 0 and cos(y)= 0. Where is sine 0?
 
fx is the derivative of the function respect to x
fy ........... y
Where is sine 0?
at zero sin is zero
 
yaho8888 said:
fx is the derivative of the function respect to x
fy ........... y
Where is sine 0?
at zero sin is zero

Your critical points will occur at points where both partials are zero. on the given intervals, what values of x and y will make both fx and fy zero?
 
solved!
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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