Mutual Inductance and wire coils

AI Thread Summary
The discussion focuses on a problem involving mutual inductance between two coils, where a time-varying current in the first coil leads to a measured voltage across the second coil. The user is attempting to calculate the mutual inductance using the formula emf2 = -M dI1/dt but is struggling to arrive at the correct answer. Initial calculations yielded a value of 80 V*s/A, but subsequent attempts suggested a possible answer closer to 472 V*s/A. There is confusion regarding the units, with a mention of mHz, which should actually be mH, indicating a misunderstanding of inductance units. Clarification on the correct units and calculations is sought to resolve the issue.
edlin
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Hi..I am new here and I am really thankful for any help that I may get :blushing:

I am stuck in a problem of mutual inductance. It seems fairly simple, yet I cannot get the correct answer.

Two coils are close to each other. The first coil carries a time-varying current given by I(t) = (4.60 A) e-0.0250tsin(377 t). At t = 0.800 s, the voltage measured across the second coil is -3.60 V. What is the mutual inductance of the coils?


So, the equation I have used is: emf2 = -M dI1/dt ...which is the voltage of the second coil equals the mutual inductance times the current with respect to time. I solved for M, but the answer is not right.

My answer was: 80 V*s/A and I got various other answers but they are incorrect.

I really, really would appreciate any help! Thankyou so much!
 
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edlin said:
Hi..I am new here and I am really thankful for any help that I may get :blushing:

I am stuck in a problem of mutual inductance. It seems fairly simple, yet I cannot get the correct answer.

Two coils are close to each other. The first coil carries a time-varying current given by I(t) = (4.60 A) e-0.0250tsin(377 t). At t = 0.800 s, the voltage measured across the second coil is -3.60 V. What is the mutual inductance of the coils?


So, the equation I have used is: emf2 = -M dI1/dt ...which is the voltage of the second coil equals the mutual inductance times the current with respect to time. I solved for M, but the answer is not right.

My answer was: 80 V*s/A and I got various other answers but they are incorrect.

I really, really would appreciate any help! Thankyou so much!
Is it by any chance more like 472 V*s/A?.
 
Well, I actually did get answers in the hundreds, but when I put my answer in, it tells me it has the wrong magnitude. And since they provide me with the units, it says mHz...so the answer is multiplied by 1/10^3... and I really don't understand why. I get no answer near that.
 
edlin said:
Well, I actually did get answers in the hundreds, but when I put my answer in, it tells me it has the wrong magnitude. And since they provide me with the units, it says mHz...so the answer is multiplied by 1/10^3... and I really don't understand why. I get no answer near that.
Are you sure it is mHz and not just mH? The units of inductance are named after Joseph Henry.

H = V·s/A
 
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