Muzzle Velocity by Analyzing Ballistic Pendulum

AI Thread Summary
The discussion focuses on deriving the muzzle velocity using conservation of energy principles in a ballistic pendulum setup. The user proposes an equation for muzzle velocity based on kinetic and gravitational potential energy, questioning whether their method is correct. They compare their derived equation with an alternative found online, which includes a mass ratio term. Participants emphasize the importance of understanding the type of collision involved and the conservation laws applicable to the scenario. Clarifications on the setup and variable definitions are suggested for better accuracy in the calculations.
ujellytek
Messages
35
Reaction score
2

Homework Statement


Finding the equation for the muzzle velocity by using conservation of energy.

2. The attempt at a solution

Ek+Eg=Ek2+Eg2
Well I'm 100% sure the kinetic energy of the ball is transferred into the catcher. The displacement is 1.9cm which is 0.019m. Mb=0.0077Kg (mass of ball) Mc=0.085Kg (mass of catcher)

Here is my work: .5Mbv^2=Mc*g*h <- this is supposed to be the total mass because the Mc and Mb become one, right? (btw that's the method my classmates used)
My method: .5Mbv^2=(Mc+Mb)*g*h
eventually v=sqrt( (2*g*h*(Mc+Mb))/Mb )

3. Relevant questions:

Is the proper equation for the muzzle velocity? v=sqrt((2*g*h*(Mc+Mb))/Mb)

I went to check this online, and I found out that the equation is supposedly supposed to be
v=(1+Mc/Mb)*sqrt(2*g*h)
 
Physics news on Phys.org
Your problem statement is rather spare. You should describe the setup and define the variables you'll be using.

ujellytek said:
Well I'm 100% sure the kinetic energy of the ball is transferred into the catcher.
You might want to rethink that. What type of collision is involved? What's conserved? What's not conserved?
 
Also, you may just want to double check that all of the values are correct.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top