My Crazy math teacher says this is solvable

  • Thread starter Thread starter The Divine Zephyr
  • Start date Start date
  • Tags Tags
    Teacher
AI Thread Summary
The math problem presented, \\x-\frac{x}{1}=\frac{12}{25}\\, leads to an impossible equation, resulting in 0 equating to a non-zero value, which indicates no solution exists. Participants suggest the original problem might be a typo, possibly intended to be \\x - \frac{x}{1} = \frac{12}{25}\\. It is emphasized that subtracting a number from itself cannot yield a positive result. The teacher confirmed that the problem was indeed a typo. The final consensus is that the equation as stated is unsolvable.
The Divine Zephyr
Messages
27
Reaction score
0
<br /> \\x-\frac {x}{1}=\frac{12}{25} ...then...\\x-x=\frac{12}{25}\\ ...then...0=\frac{12}{25}<br /> <br />


... I hope not...

Is there a way? It was on homework and he says that all of them have answers. He didnt direct any comment on this problem. btw, only the first part is actaully on the problem, the part after the first "then" is what I got.
 
Physics news on Phys.org
Your problem has no solution in any field where 1 is the multiplicative identity, much less in the real numbers. The problem may have been a typo of x - 1/x = 12/25.
 
did the problem ask you to solve for x? x is not solvable...100%... period
that might be a typo or something alike...
you might want to make sure the question is not "is x solvable" j/k
 
A number "n" cannot be subtracted by an identical value and result in a positive value.

The answer could be something like "unsolvable."
 
Yeah, I emailed my teacher and he said it was a typo ;)
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top