Name of this type of function.

  • Thread starter Thread starter Square1
  • Start date Start date
  • Tags Tags
    Function Type
AI Thread Summary
The function y = a^(1/x) is identified as a specific type of exponential function, while y = a^x is a more general form of exponential function. The first function is considered a subset of the second due to its more complex exponent involving a variable. Both functions share similar characteristics, but the growth rate of the first function is less intense than that of the second, depending on the constant "a." The discussion highlights the terminology differences in English and Russian regarding these functions, emphasizing their mathematical relationship.
Square1
Messages
143
Reaction score
1
Hi all. Can someone tell me the name for the following type of function:

y = a^(1/x)

where:
a = a constant
x = the variable...

Also, am I right, that the next function is called an exponential function?

y = a^x

Are the two functions related? Is the first some type of subset of the second?

Thank-ya!
 
Mathematics news on Phys.org
Yes, that's the exponential functions and the second (y = a^x) is common case of the first (y = a^(1/x) ). Therefore they have similar characteristics. In this particular case function number 1 will increase or decrease (it depends on sign of the constant "a") less intensively than function number 2.
 
Ok so both are exponential because the variable x is somewhere with the exponent.

One thing though. You said that the second is a case of the first? That's odd I would think that the first is a case of the second since the first has a little bit more complicated looking exponent. Any comments on that?
 
I don't know why really in English language this type of functions called "exponential", because for instance in Russian there are different names for y(x)=x^e ("экспоненциальная функция" = "exponential function") and y(x)=a^x ("показательная функция" ≈ "index-of-power function")

No, the first is a subcase of the second, but the second is GENERAL case of the first)
There is math term known as 'сombined function' and y1(x) = a^(1/x) is combination of y2(z)=a^z and z(x) = 1/x.
In other words:
y2(z) = a^z (here z is intermediate variable) = a^z(x) = a^(1/x) = y2(z(x)) = y1(x).
It's like russian matryoshka))
 
Seemingly by some mathematical coincidence, a hexagon of sides 2,2,7,7, 11, and 11 can be inscribed in a circle of radius 7. The other day I saw a math problem on line, which they said came from a Polish Olympiad, where you compute the length x of the 3rd side which is the same as the radius, so that the sides of length 2,x, and 11 are inscribed on the arc of a semi-circle. The law of cosines applied twice gives the answer for x of exactly 7, but the arithmetic is so complex that the...
Thread 'Unit Circle Double Angle Derivations'
Here I made a terrible mistake of assuming this to be an equilateral triangle and set 2sinx=1 => x=pi/6. Although this did derive the double angle formulas it also led into a terrible mess trying to find all the combinations of sides. I must have been tired and just assumed 6x=180 and 2sinx=1. By that time, I was so mindset that I nearly scolded a person for even saying 90-x. I wonder if this is a case of biased observation that seeks to dis credit me like Jesus of Nazareth since in reality...
Fermat's Last Theorem has long been one of the most famous mathematical problems, and is now one of the most famous theorems. It simply states that the equation $$ a^n+b^n=c^n $$ has no solutions with positive integers if ##n>2.## It was named after Pierre de Fermat (1607-1665). The problem itself stems from the book Arithmetica by Diophantus of Alexandria. It gained popularity because Fermat noted in his copy "Cubum autem in duos cubos, aut quadratoquadratum in duos quadratoquadratos, et...

Similar threads

Replies
3
Views
1K
Replies
7
Views
1K
Replies
9
Views
2K
Replies
1
Views
2K
Replies
9
Views
4K
Replies
1
Views
1K
Replies
2
Views
973
Back
Top