Natural domain to define f(z)=loglog

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Homework Help Overview

The problem involves determining the natural domain for the function f(z) = log(log(z)), where log(z) is defined using the principal branch of the logarithm function with the argument constrained to -π < arg(z) < π.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the representation of the argument of log(z) and question the inclusion of the term "+2πk". There is an exploration of when log(z) corresponds to a negative real number and the implications for the domain of f(z).

Discussion Status

The discussion is ongoing, with participants raising questions about the conditions under which log(z) is a negative real number and the implications for defining the function f(z). Some guidance has been offered regarding the need to avoid certain values of z, but no consensus has been reached.

Contextual Notes

There is a mention of potential terminology issues regarding the characterization of log(z) being zero and its relevance to the domain of f(z).

justin_huang
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Homework Statement



Let log z be the principal branch of the logarithm function defined −pi < arg z < pi
the domain to define f(z)=loglog z??

Homework Equations





The Attempt at a Solution


I already know how to represent the arg z by arctanb/a+2pi*k
how can I get arctan [Re (log z)/Im (log z)]+2pi*k
or any other method?
 
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justin_huang said:
I already know how to represent the arg z by arctanb/a+2pi*k

The "[itex]+2\pi k[/itex] shouldn't be here right?

how can I get arctan [Re (log z)/Im (log z)]+2pi*k
or any other method?

So basically, you want to know when

[tex]-\pi<arg(log(z))<\pi[/tex]

surely this correspond to log(z) being a negative real number.

So, you must calculate log(z) in some way (do you have a formula for it) and see when it is a negative real number. These are the z we don't want.
 
I considered log(z)=0 to be part of "log(z) is a negative real number", but this is probably not standard terminology. So yes, you also need to make sure that log(z) isn't 0...
 
micromass said:
The "[itex]+2\pi k[/itex] shouldn't be here right?



So basically, you want to know when

[tex]-\pi<arg(log(z))<\pi[/tex]

surely this correspond to log(z) being a negative real number.

So, you must calculate log(z) in some way (do you have a formula for it) and see when it is a negative real number. These are the z we don't want.

thanks so much
 

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