Navigating Math After High School: Where to Go Next?

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After completing college algebra with trigonometry, the most recommended next step is to begin studying calculus, specifically "Calculus 1," as it builds on the knowledge gained from pre-calculus. While geometry can be pursued later, starting calculus while the material is fresh is advised. Following the completion of Calculus 1, the logical progression typically leads to Calculus II or linear algebra, depending on individual goals. Establishing a structured curriculum is essential to avoid aimless study. Ultimately, the direction should align with personal academic or career objectives.
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OK, I'm teaching myself all the stuff I didn't learn in high school. I just finished up college algebra with trig, and now I don't know which way to go from here. I was thinking maybe I should get a good geometry textbook and go with that, or maybe some more trig or more advanced algebra. I don't know. What is the most natural route from one subject to the other?
 
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Calculus.

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Beginning Calculus or "Calculus 1" is the most popular next choice. You could choose Geometry if you did not learn it well earlier, but you just finished studying a "Pre-Calculus" book and this has prepared you for studying Beginning Calculus; best to start it now while you are still fresh. Besides, you can always choose Geometry later.
 
Thanks for the replies, folks! So calculus it is. I have a beginning textbook. So, after that, what is the next natural course? Do I just go on to calc II, or linear algebra, or what? I just want to put together a natural curriculum to follow, and not jump around blindly. What are the tried and true courses?
 
What's your ultimate goal?
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Essentially I just have this problem that I'm stuck on, on a sheet about complex numbers: Show that, for ##|r|<1,## $$1+r\cos(x)+r^2\cos(2x)+r^3\cos(3x)...=\frac{1-r\cos(x)}{1-2r\cos(x)+r^2}$$ My first thought was to express it as a geometric series, where the real part of the sum of the series would be the series you see above: $$1+re^{ix}+r^2e^{2ix}+r^3e^{3ix}...$$ The sum of this series is just: $$\frac{(re^{ix})^n-1}{re^{ix} - 1}$$ I'm having some trouble trying to figure out what to...

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