How can I calculate the force vector for a mortar in a computer game?

[s w]

I'm in the process of created a computer game and I want to introduce a mortar into the game. What I want to do is given the initial position, target position, and target height, calculate the force vector that is needed to launch the mortar so it hits the target height and target distance. The reason I put a target height in there is so the mortar is doing an appropriate parabolic arc. I don't want it to just do a slight arc and hit the target, I want it to go relatively high but still remain inside the bounds of the level.

So to summarize. I know the initial position, target position, target height, mass of the object, and gravity (assume no drag) and I want to know the force vector needed. It also must be said that the initial and target positions lie in all 3 planes. So I'd really like to be able to hit a target that is higher or lower than the initial position if possible. As for the target height, that is the height above the initial position.

 

[sentinel]

it depends if you have the resisting force of air and in what magnitude?F=kmv or F=kmv.v or ... and this depends on your estimated speed, without resistance: X=V*COSa*t,Y=(V*SINa*t)-((1/2)*g*t.t)

 

[s w]

Quoted from above.

(assume no drag)

 

[sentinel]

i don't study physics in english so i am not familiar with some words but anyway just use the equations i mentioned in three dimension(x,y,z) and simply use F=ma thing on them, plus ,if you want to calculate the resistance first check your estimated speed with some table to see if the resistance is kmv or kmv.v and also you can estimate it by using the taylors formula or somethinh(f(X)=a1+a2x+a3xx+a4xxx+...) then cut off from xx.

 

[PJC01]

Thank you for reaching out to us for assistance with your computer game. To calculate the trajectory of a mortar, we can use the following equation:

y = y0 + v0y*t - 0.5*g*t^2

Where:
y is the vertical position of the mortar at any given time t
y0 is the initial vertical position of the mortar
v0y is the initial vertical velocity of the mortar
g is the acceleration due to gravity (9.8 m/s^2)
t is the time elapsed since the mortar was launched

To ensure that the mortar hits the target height and distance, we can set up a system of equations using the above equation and the given information. This will allow us to solve for the initial vertical velocity (v0y) and the time of flight (t) needed to hit the target.

To calculate the force vector needed, we can use Newton's second law:

F = m*a

Where:
F is the force vector needed
m is the mass of the mortar
a is the acceleration of the mortar, which can be calculated using the initial vertical velocity (v0y) and the time of flight (t) obtained from the previous equations.

We can also take into account the target height by adjusting the initial vertical position (y0) in the trajectory equation.

Please note that this is a simplified approach and may not take into account other factors such as air resistance. Depending on the level of accuracy needed for your game, you may need to incorporate more complex equations and variables.

I hope this information helps in creating a realistic and enjoyable experience for your players. Good luck with your game!