Need formula for absolute pressure/force problem

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To solve the absolute pressure at the bottom of a swimming pool, the formula used is P = ρgh, where P is pressure, ρ is the density of water, g is the acceleration due to gravity, and h is the depth of the water. For the total force on the bottom of the pool, the formula is F = PA, where F is force, P is pressure, and A is the area of the pool's bottom. The weight of the water and air supported by a unit area can be calculated using the same pressure formula, taking into account both the water and atmospheric pressure. Hydrostatic pressure is relevant in this context, as it describes the pressure exerted by a fluid at equilibrium due to the force of gravity. Understanding these formulas is essential for solving the quiz questions effectively.
mbondur
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I am taking an online quiz and I have been looking for 3 days for a way to solve this problem (all I need are the formulas, the math I can handle on my own).

It's a 2 part question. Here goes.

What is the absolute (!) pressure on the bottom of a water filled swimming pool 25.0 m by 12.40 m whose uniform depth is 1.86 m ?

and then

What is the total force on the bottom of that swimming pool?
 
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What is the weight of the water and air supported by a unit of area of the pool bottom?
 
Welcome to PF!
Have you heard of hydrostatic pressure?
 
The water and air are normal weight at sea level, and no, hydrostatic pressure is new to me.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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