NEED Help (Basically a Law of Cosines problem)

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The discussion revolves around a problem involving the elongation of cables AC and AB, where the user initially attempts to solve it using similar triangles but encounters difficulties. The key issue identified is that the triangles formed before and after elongation are not similar due to changing angles. A hint from the professor suggests using the Law of Cosines to find the new lengths of AC and AB after elongation. The user expresses frustration with the problem and acknowledges a lack of geometry knowledge. Ultimately, the conversation highlights the importance of understanding triangle properties in solving the problem effectively.
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[SOLVED] NEED Help (Basically a Law of Cosines problem)

So in this problem, all I have to do is to solve it is find out by how much cables AC and AB elongate.
Picture4.png


I thought I could just break it into two Right triangles and just use similar triangles (before and after elongation)

If you look at the upper right triangle, let's call it ACO, where O denotes the point on the wall halfway between C and B.

Then I tried doing,
\frac{AC}{OA}=\frac{AC'}{OA'}

\Rightarrow AC'=\frac{300}{300\cos30}*(300\cos30+2)

But this does not work. . . why the hell not??

My prof gave us the hint: "Use Law of Cosines to find the lengths of AC or AB after elongation"

How do I use Law of Cos if I don't know the angles after elongation, and moreover what is wrong with the process I tried?

I hate all of my classes. I miss physics.

Casey
 
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Mechanics of Materials eh?

http://www.mediafire.com/?0fmwmgeogi6
 
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Where did you get that? Anyway, thanks! I think the dotted line should be labeled L_{AC}' though. But now I see it. I never took a geometry course so this stuff makes me insane.

Do you know why my original method does not work?
 
because they won't be similar triangles...
 
coffeebean51 said:
because they won't be similar triangles...

ummm. . . because the angle changes right?
 
Yeah.
 
Short and to the point. I like your style beans :wink:

Welcome aboard,
Casey
 
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