Need Help with Exam Prep - E-field and Electric Flux Problems

[matt4u]

Need urgent Help - Exam tomorrow

Homework Statement

question 1: A 2.0 cm piece of wire with a linear charge density 4.0 micro C/m is bent into a quarter circle. a) what is magnitude and direction of the E-field at the center of the curvature? b) what's the distance from the wire to the center of the curvature?

question 2: A conical megaphone sits in a uniform electric field of strength 200N/C. a) if the megaphone is 1.00 m tall with the large hole measuring 0.50 m in diameter and the small hole measure 8.00 cm in diameter, what is the electric flux through the megaphone? b) what is the flux if it is tilted by 90 degrees?

Please help me guys...really appreciate it

Homework Equations

The Attempt at a Solution

 

[NateD]

Question 1: a) The magnitude of the electric field at the center of the curvature is zero because the electric field of any two opposite charges cancel each other out. b) The distance from the wire to the center of the curvature is equal to the radius of the quarter circle which is equal to 1 cm. Question 2: a) The electric flux through the megaphone is given by the equation Φ = EA, where E is the strength of the electric field (200N/C) and A is the area of the megaphone (2πr(h + r), where h is the height of the megaphone and r is the radius of the large hole). Therefore, the electric flux is Φ = 200N/C * (2π(0.5m)(1.0m + 0.5m)) = 6283.18N/C. b) If the megaphone is tilted by 90 degrees, the electric flux is zero because the electric field is perpendicular to the surface of the megaphone.