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Find the second-order partial derivatives of the given function. In each case, show that the mixed partial derivatives f_{xy} and f_{yx} are equal.
Function:
f(x,y)=x^{3}+x^{2}y+x+4
My work (Correct me if I am wrong):
\frac{\partial{f}}{\partial{x}}}=3x^{2}+2xy+1
\frac{\partial{f}}{\partial{y}}}=x^{2}
f_{xx}=6x+2y
f_{yy}=0
f_{xy}=6x+2y
f_{yx}=0
If I am correct, which I am probably not, how could f_{xy} possibly be equal to f_{yx}? Shouldn't that always be true anyways? If that's so, then obviously I messed up somewhere. Please help!
Function:
f(x,y)=x^{3}+x^{2}y+x+4
My work (Correct me if I am wrong):
\frac{\partial{f}}{\partial{x}}}=3x^{2}+2xy+1
\frac{\partial{f}}{\partial{y}}}=x^{2}
f_{xx}=6x+2y
f_{yy}=0
f_{xy}=6x+2y
f_{yx}=0
If I am correct, which I am probably not, how could f_{xy} possibly be equal to f_{yx}? Shouldn't that always be true anyways? If that's so, then obviously I messed up somewhere. Please help!