Need help solving this logarithmic problem

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SUMMARY

The equation \( e^{3x} \cdot (e^4)^x = e^{4x} - 15 \) can be simplified using the properties of exponents. By applying the property \( (a^b)^c = a^{bc} \), the equation transforms to \( e^{3x} \cdot e^{4x} = e^{4x} - 15 \). Further simplification using \( a^b \cdot a^c = a^{b+c} \) leads to the conclusion that the original interpretation of the equation has no real solutions.

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(e3x)(e4)x = e4x -15

Could use help solving this here within the next 40 minutes, appreciate the help, this is the last one out of a 75 question take home test and I'm having soo many issues.

Thanks in advanced for the help.
 
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Hello and welcome to MHB!:

Has your professor given you permission to get outside help with this graded assignment?
 
Yes only for 3 questions and we have to post where we got the outside help from.
 
Okay, we are given:

$$e^{3x}\cdot \left(e^4 \right)^x=e^{4x}-15$$

I would first use the property of exponents $$\left(a^b \right)^c=a^{bc}$$ on the second factor on the left, and so we have:

$$e^{3x}\cdot e^{4x}=e^{4x}-15$$

What do we get when we apply the property $$a^b\cdot a^c=a^{b+c}$$ on the left?
 
I have it now, I was reading it as e4x-15 not e4x-15

Thanks for the help everyone
 
Your original interpretation has no real solutions. Glad you figured it out. :D
 

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