Need help understanding this concept on field intensity

In summary, The question is asking for the gravitational field intensity at a height of 300.0 km from Earth's surface. This can be calculated using the equation for gravitational field intensity near a point mass, as the point in question is outside of Earth's sphere. This is because for points outside the sphere, the Earth behaves as if all of its mass were concentrated at its center. This can be verified using calculus by calculating the gravitational field due to one small mass and integrating over the volume of the sphere.
  • #1
aeromat
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Homework Statement


We are looking at gravitational field intensity in particular here, and using the Earth as an example. The question states: Calculate the gravitational field intensity at a height of 300.0 km from Earth's surface.

Why is it that: Since the point in question is outside of the sphere of Earth, the gravitational field there is the same as it would be if Earth's mass was concentrated at a point in Earth's centre. Therefore the equation for the gravitational field intensity near a point mass applies?

I don't understand how you could have the same gravitational field concentrated at a point, and it being the same even if you are 300km FAR FROM EARTH? Is this implying that the intensity is the same, because that doesn't make sense to me.
 
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  • #2
It's not the gravitational field that's concentrated at a point; it's the mass. A perfect sphere behaves gravitationally as if all of its mass were concentrated at its center, but only for points outside the sphere. As for why, you can use calculus to verify the theorem by calculating the gravitational field due to one small mass of volume dV, then integrating over the volume of the sphere.
 

What is field intensity?

Field intensity, also known as electric field strength, is a measure of the strength of an electric field at a particular point in space. It is defined as the amount of force per unit charge that would be exerted on a positive test charge at that point.

How is field intensity related to electric charge?

The electric field intensity at a point is directly proportional to the amount of electric charge present at that point. This means that as the amount of charge increases, the field intensity will also increase.

What is the difference between field intensity and electric potential?

Field intensity and electric potential are related concepts, but they are not the same. Field intensity measures the strength of the electric field, while electric potential measures the potential energy per unit charge at a particular point in the field.

How is field intensity calculated?

Field intensity is calculated by dividing the force exerted on a test charge by the magnitude of the charge. Mathematically, it can be represented as E = F/q, where E is the field intensity, F is the force, and q is the charge.

Why is field intensity important in physics?

Field intensity is important in physics because it helps us understand the behavior of electric fields and how they interact with charged particles. It is also a crucial concept in many practical applications, such as in the design of electrical circuits and devices.

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