Need Help with a Triangular Loop Problem?

  • Thread starter Thread starter sfgoat
  • Start date Start date
  • Tags Tags
    Loop
AI Thread Summary
The discussion revolves around a triangular loop problem where the user seeks clarification on a test question they answered incorrectly. The key point raised is whether the equation sin(φ) = 1 applies to all segments of the loop. It is confirmed that while this holds for the ac segment, it does not for the other two segments, specifically bc, where sin(π) or sin(2π) equals zero. This leads to the conclusion that the force on the bc segment would indeed be zero. The conversation encourages further exploration of the problem for better understanding.
sfgoat
Messages
10
Reaction score
0
This is a question I got wrong on a test and would like to see if I can get someone to show me how to do it properly. Snapped a pic . See below please. Thanks.
 

Attachments

  • 1397061439183.jpg
    1397061439183.jpg
    14 KB · Views: 428
  • 1397061473682.jpg
    1397061473682.jpg
    32.9 KB · Views: 442
Physics news on Phys.org
You've written ##\sin(\phi )=1## at the top. And that is true for the ac segment. But is it true for the other two segments?
 
So would the force on the bc segment be zero since the sin(pi or 2pi) would be zero
 
yep, you got it. keep going :)
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'
Figure 1 Overall Structure Diagram Figure 2: Top view of the piston when it is cylindrical A circular opening is created at a height of 5 meters above the water surface. Inside this opening is a sleeve-type piston with a cross-sectional area of 1 square meter. The piston is pulled to the right at a constant speed. The pulling force is(Figure 2): F = ρshg = 1000 × 1 × 5 × 10 = 50,000 N. Figure 3: Modifying the structure to incorporate a fixed internal piston When I modify the piston...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top