Need help with Gravitational Field Strength question

AI Thread Summary
To find the gravitational field strength at a satellite orbiting Earth at a distance of 3 times the Earth's radius, the gravitational force equation Fg = Gm1m2/d^2 is used, where d is the distance from the Earth's center. The gravitational field strength decreases with the square of the distance from the center of the Earth, meaning g' = GM(Earth)/d^2. The satellite's distance from the Earth's center is 4R (3R above the surface plus 1R for Earth's radius). Understanding this relationship clarifies how to calculate gravitational field strength at that distance. The discussion emphasizes the inverse square law of gravitation and the importance of distance in these calculations.
ultimatesoulx
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Homework Statement


A satellite orbites Earth at a distance of 3rEARTH, above Earth's surface. What is the magnitude of gravitational field strength at the point where the satellite is?

Homework Equations


Fg= Gm1m2/d^2 (m1=mass 1, m2=mass2)
F1/F2 = D2^2/D2^2 (D1 is a variable, and so is D2, so it represents Distance 1 and Distance 2)

The Attempt at a Solution


I don't understand how it works? You have the equation for the radius of Earth, 6400km, but not much else other than the G which is 6.67x10^-11. I'm not sure how to tackle this, and it's confusing me a lot. I tried applying Fg= Gm1m2/d^2, but there is no mass on them.P.s on a secondary note, if I am doing a question where it compares 2 masses that have an attraction (i.e 36N, how do you find the distances/mass?)
 
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ultimatesoulx said:

Homework Statement


A satellite orbites Earth at a distance of 3rEARTH, above Earth's surface. What is the magnitude of gravitational field strength at the point where the satellite is?


Homework Equations


Fg= Gm1m2/d^2 (m1=mass 1, m2=mass2)
F1/F2 = D2^2/D2^2 (D1 is a variable, and so is D2, so it represents Distance 1 and Distance 2)


The Attempt at a Solution


I don't understand how it works? You have the equation for the radius of Earth, 6400km, but not much else other than the G which is 6.67x10^-11. I'm not sure how to tackle this, and it's confusing me a lot. I tried applying Fg= Gm1m2/d^2, but there is no mass on them.


P.s on a secondary note, if I am doing a question where it compares 2 masses that have an attraction (i.e 36N, how do you find the distances/mass?)

The gravitational attraction between masses m1 and m2, d distance apart, is F=Gm1m2/d2. If the objects are spheres d means the distance between their centres.

The gravitational field strength means the force of gravity exerted on unit mass. At the surface of the Earth it is g=9.8 m/s2:

9.8=GM(Earth)/R2, where R is the radius of the Earth.

The gravitational field strength at distance d from the centre of Earth is g'=GM(Earth) /d2.
If you divide the equations in bold you get

g'/9.8=R2/d2.

The satellite is 3R above the surface of Earth. How far is it from the centre of Earth?

ehild
 
The gravity of the Earth at some distance is inversely proportional to the square of the distance from its center. At the surface, this is g. That, and the distance of the satellite from the Earth, should be enough.
 
I understand the question now, thanks for the help!
 
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